for the discovery of neutrino oscillations, which shows that neutrinos have mass
Often see oscillations treated with plane waves
Flavour basis $\nu_\alpha$ can be related to mass basis $\nu_i$ by
$$\left| \nu_\alpha \right\rangle = \sum_i U_{\alpha i}^* \left| \nu_i \right\rangle \, ,$$
where $U_{\alpha i}$ is the mixing matrix, and its spacetime evolution is
$$\left| \nu_\alpha(t, x) \right\rangle = \sum_i U_{\alpha i}^* e^{-i (E_i t - p_i x)} \left| \nu_i \right\rangle \, .$$
Amplitude at detection is given by
where $T = t_d - t_p$ and $L = x_d - x_p$.
Amplitude at detection is given by
where $T = t_d - t_p$ and $L = x_d - x_p$.
Transition probability found by
Giunti [1] gives several reasons to consider wave packets
no source of waves vibrates indefinitely
the particle cannot be described by an unlocalized plane wave
Beuthe [2] adds that,
“this approach implies a perfectly well-known energy–momentum and an infinite uncertainty on the space–time localization of the oscillating particle. Oscillations are destroyed under these assumptions.”
$$\left| \nu_\alpha(t, x) \right\rangle = \sum_i U_{\alpha i}^* \psi_i(t, x) \left| \nu_i \right\rangle \, ,$$
where
Nussinov [3] argued that wave packets cause decoherence
Kayser [4] first to study oscillations with wave packets, and Giunti [5] first to obtain explicit results with Gaussians
Can obtain analytic results!
“A gaussian momentum distribution is the most convenient one for the calculation of several integrations …
Other distributions which are sharply peaked around an average momentum lead to the same results after their approximation with a gaussian …
Therefore, the gaussian momentum distributions can be taken as approximations of the real momentum distributions from the beginning.” [6]
A Gaussian is described by its first two moments (mean and variance).
We can have non-Gaussian wave packets!
Conditions on when a distribution $f(p) = \exp [-g(p)]$
can be approximated by a Gaussian [7].
Expanding about minimum $p = P$, we require
Neutrinos in the context of the Mössbauer effect,
described by a Lorentzian wave packet [8, 9]
$$\tilde\psi(p; \bar{p}, \gamma) = \mathcal{N} \left[ \frac{\gamma}{(p - \bar{p})^2 + \gamma^2} \right]$$
Moments undefined. Cannot be approximated by a Gaussian!
Can be expressed in a Lorentz invariant form
$$\tilde\psi(p_\mu; a_\mu) = \mathcal{N} \exp \left[ -a_\mu p^\mu \right] \, ,$$
where $a_\mu = (\alpha, -\beta) \in \mathbb{C}^{2}$ and transforms as a vector.
Let us reconsider Gaussian wave packets
$$\psi(p; \bar{p}, \sigma_p) = \mathcal{N} \exp \left[ -\frac{(p - \bar{p})^2}{4 \sigma_p^2} \right] \, .$$
Let us reconsider Gaussian wave packets
$$\psi(p; \bar{p}, \sigma_p) = \mathcal{N} \exp \left[ -\frac{(p - \bar{p})^2}{4 \sigma_p^2} \right] \, .$$
Gaussian minimises Heisenberg-Robertson uncertainty relation
$$\sigma_x \sigma_p = \left| \frac{1}{2i} \left\langle [\hat{x}, \, \hat{p}] \right\rangle \right| = \frac{\hbar}{2} \, .$$
Assuming that position and momentum are independent
More generally, can have non-vanishing covariance
$$\sigma_x^2 \sigma_p^2 - \sigma_{x p}^2 = \left| \frac{1}{2i} \left\langle [\hat{x}, \, \hat{p}] \right\rangle \right|^2$$
One obtains squeezed Gaussian wave packets
$$\psi(p; \bar{x}, \bar{p}, \sigma_p) = \mathcal{N} \exp \left[ -\frac{(p - \bar{p})^2}{4 \sigma_p^2} + i \bar{x} p \right]$$
Define relativistic velocity operator
$$\hat{v} \equiv i [\hat{H}, \hat{x}] = \frac{\hat{p}}{\hat{H}}$$
Minimise uncertainty between position and velocity
$$\sigma_x^2 \sigma_v^2 - \sigma_{x v}^2 = \left| \frac{1}{2i} \left\langle [\hat{x}, \, \hat{v}] \right\rangle \right|^2$$
Minimise uncertainty between position and velocity
$$\sigma_x^2 \sigma_v^2 - \sigma_{x v}^2 = \left| \frac{1}{2i} \left\langle [\hat{x}, \, \hat{v}] \right\rangle \right|^2$$
Squeezed RMU wave packets! Generalised from Ref. [10]
$$\tilde\psi(E_p, p; \alpha, \beta) = \mathcal{N} \exp \left[ -\alpha E_p + \beta p \right] \, ,$$
where $\alpha, \beta$ determined by the moments of velocity and space(time)
Squeezed RMU wave packets! Generalised from Ref. [10]
$$\tilde\psi(E_p, p; \alpha, \beta) = \mathcal{N} \exp \left[ -\alpha E_p + \beta p \right] \, ,$$
where $\alpha, \beta$ determined by the moments of velocity and space(time)
Reduce to Gaussians in non-relativistic limit… and to Lorentzians in the ultra-relativistic limit! (In configuration space and neglecting mass)
Plane wave: $$\mathcal{A}_{\nu_\alpha \to \nu_\beta}(T, L) = \sum_i U_{\alpha i}^* e^{-i (E_i T - p_i L)} U_{\beta i}$$
Gaussian: $$\mathcal{A}_{\nu_\alpha \to \nu_\beta}(T, L) \sim \sum_i U_{\alpha i}^* \exp \left[ -\frac{(L - \bar{v}_i T)^2}{4 \sigma_x^2} - i (\bar{E}_i T - \bar{p}_i L) \right] U_{\beta i}$$
RMU: $$\mathcal{A}_{\nu_\alpha \to \nu_\beta}(T, L) \sim \sum_i U_{\alpha i}^* \frac{(T - i \alpha) m_i K_1\left( -m_i \sqrt{(T - i \alpha)^2 + (L - i \beta)^2} \right)}{\sqrt{(T - i \alpha)^2 + (L - i \beta)^2}} U_{\beta i}$$
In general, $\sigma_x^{(RMU)}(t) \leq \sigma_x^{(G)}(t)$ for all time
Controversy in early 2000s whether group velocities can be equal [12-14]
Consensus is debate settled as “no” from kinematical arguments
Let's be more careful!
Should one take $\bar{v} = \langle p \rangle / \langle E \rangle$?
In general, one has $\bar{v} = \langle \partial_p E \rangle \neq \langle p \rangle / \langle E \rangle$!
RMU wave packets have $\bar{v} = \langle \partial_p E \rangle = \mathrm{Re}(\beta) / \mathrm{Re}(\alpha)$, while $$\frac{\langle p \rangle}{\langle E \rangle} = \frac{\mathrm{Re}(\beta)}{\mathrm{Re}(\alpha)} \left( \frac{1}{1 - \chi_{m, \mathrm{Re}(\alpha), \mathrm{Re}(\beta)}} \right) \, .$$
Only agrees in semi-classical regime, when the wave packets are sufficiently spread with respect to the Compton scale
Evan Gale | e.gale@uq.edu.au