Physical Review D 107, 056023 (2023)
Originally proposed by Unruh [1], then simplified by DeWitt [2].
Couples a two-level system to a quantised scalar field ˆϕ(→x)
Polarisation or 'monopole' operator exchanges energy levels
ˆμ=|g⟩⟨e|+|e⟩⟨g|Originally proposed by Unruh [1], then simplified by DeWitt [2].
Couples a two-level system to a quantised scalar field ˆϕ(→x)
Field can be decomposed as superposition of plane wave modes
ˆϕ(→x)=1(2π)3/2∫d3k√2ω(→k)(ˆa(→k)e−i→k⋅→x+H.c.)Considered by Unruh and Wald for a box detector [3]
ˆHI=λ∫d3xˆμ(→x)⊗ˆϕ(→x)with a position-dependent monopole operator of the form
ˆμ(→x)≡ψ∗g(→x)ψe(→x)|g⟩⟨e|+ψ∗e(→x)ψg(→x)|e⟩⟨g|Alternative extension considered by Stritzelberger and Kempf [4]
Detector's free Hamiltonian now includes a kinetic term
ˆHD=ˆ→p22M+E|e⟩⟨e|Full atom-light interaction treated by Wilkens [5]
Problem: both extensions assume a non-relativistic detector!
Problem: both extensions assume a non-relativistic detector!
Can introduce relativistic centre of mass in two different ways:
Let's consider both models, starting with second-quantised case
Relativistic second-quantised detector model proposed by Unruh [1]
Giacomini and Kempf [6] simplified by restricting to one-particle sector
Quantise the detector in a boosted frame with momentum →p
ˆHD=√ˆ→p2+ˆM2.To describe internal energy, we must quantise the mass-energy
ˆM=Mg|g⟩⟨g|+Me|e⟩⟨e|,where
ˆM|j⟩=Mj|j⟩.Interaction Hamiltonian should have the form
This Hamiltonian coincides with the non-relativistic expression
Interaction Hamiltonian should have the form
But we have to be a little careful!
Q. What time parameter does the Hamiltonian generate time translations for? [8]
A. Inertial detector. Generate time translations wrt coordinate time t
Interaction Hamiltonian should have the form
But we have to be a little careful!
Q. How do we define the position states |→x⟩(1st)D?
A. Take states to be Fourier transform of momentum eigenstates
|→x⟩(1st)D≡1(2π)3/2∫d3pe−i→p⋅→x|→p⟩D.Interaction Hamiltonian should have the form
But we have to be a little careful!
Q. How are the coupling constants between models related?
A. Take couplings to coincide for detector at rest
λ(2nd)=√2(M2g+M2e)λ(1st).First-quantised model
Second-quantised model
Different localisations are given by
to the final state via spontaneous emission of the atom-detector
|Ψf⟩=|→pf,g⟩D⊗ˆa†(→k)|0⟩.Transition amplitude and probability found from
A|→pi,e,0⟩→|→pf,g,1→k⟩=⟨Ψf|ˆU(tf,ti)|Ψi⟩,P|→pi,e,0⟩→|g⟩=∫d3k∫d3pf|A|→pi,e,0⟩→|→pf,g,1→k⟩|2.Transition rate given as a functional of the detector wave function (probability density function), convolved with a 'template function'
Transition rate given as a functional of the detector wave function (probability density function), convolved with a 'template function'
Assume detector has Gaussian profile
ψi(→p;→pD)=(L22π)3/4exp(−L24|→p−→pD|2).Can obtain analytic results for detector at rest →pD=→0
˙P(1st)rel.[ψi]∼eL2M2e4K1(L2M2e4),˙P(2nd)rel.[ψi]∼U(12,0,L2M2e2).Newton and Wigner [10] defined a relativistic position operator
by requiring it satisfy a set of invariance conditions
Coincides with the non-relativistic position operator [11]
Philips [12] defined a Lorentz-invariant position operator
In second-quantised formalism, Philips' position state is equivalent to the action of field operator on vacuum |→xp⟩≡ˆψ(→x)|0⟩
Localisation schemes not first- versus second-quantised.
Correspond to different representations with associated wave equations
Q. How should we interpret the results of these two localisations?
A. It's unclear.
Evan Gale | e.gale@uq.edu.au